TUGAS
ANREG HAL 188-191
Latihan 1
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ANOVAb
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Model
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Sum of Squares
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df
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Mean Square
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F
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Sig.
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1
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Regression
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1161.665
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3
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387.222
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9.771E3
|
.000a
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Residual
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2.735
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69
|
.040
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Total
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1164.399
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72
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a. Predictors: (Constant),
interaksiBBdanTB, tinggibadan, beratbadan
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b.
Dependent Variable: indeks massatubuh
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Coefficientsa
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Model
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Unstandardized Coefficients
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Standardized Coefficients
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t
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Sig.
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B
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Std. Error
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Beta
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1
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(Constant)
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13.472
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1.485
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9.071
|
.000
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beratbadan
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1.046
|
.049
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2.752
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21.260
|
.000
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tinggibadan
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-.092
|
.010
|
-.180
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-8.893
|
.000
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interaksiBBdanTB
|
-.004
|
.000
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-1.690
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-11.865
|
.000
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a.
Dependent Variable: indeksmasatubuh
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Y
= β0+ β1X1 +β2X2 +β3X3
IMT
= 13.472 + 1.046 BB -.092 TB -0.004 interaksi BB dan
TB
Hipotesaintersepdan slop = Setiapkenaikan BB akanmempengaruhinillai
IMT namuninteraksikeduanya
BB dan TB tidakmempengaruhinilai IMT.
|
ANOVAb
|
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|
Model
|
Sum of Squares
|
df
|
Mean Square
|
F
|
Sig.
|
|
|
1
|
Regression
|
75.863
|
3
|
25.288
|
1.603
|
.197a
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Residual
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1088.537
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69
|
15.776
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Total
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1164.399
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72
|
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a.
Predictors: (Constant), interaksijeniskelamindanumur, umur, jeniskelamin
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b.
Dependent Variable: indeksmassatubuh
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Coefficientsa
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||||||
|
Model
|
Unstandardized Coefficients
|
Standardized Coefficients
|
t
|
Sig.
|
||
|
B
|
Std. Error
|
Beta
|
||||
|
1
|
(Constant)
|
-25.817
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45.760
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-.564
|
.574
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jeniskelamin
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33.589
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24.833
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3.859
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1.353
|
.181
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umur
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3.973
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4.196
|
.508
|
.947
|
.347
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interaksijeniskelamindanumur
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-3.075
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2.283
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-3.778
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-1.347
|
.182
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a.
Dependent Variable: indeksmassatubuh
|
|
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Y
= β0+ β1X1 +β2X2 +β3X3
IMT
= -25.817 + 33.589 JK + 3.973umur
-3.075 interaksijeniskelamindanumur
Hipotesaintersepdan slop =
Setiapkenaikanumurdanjeniskelaminmempengaruhinilai IMT
namuninteraksikeduanyatidakmempengaruhinilaiIMT .
|
ANOVAb
|
||||||
|
Model
|
Sum of Squares
|
df
|
Mean Square
|
F
|
Sig.
|
|
|
1
|
Regression
|
1383.154
|
3
|
461.051
|
7.959
|
.000a
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Residual
|
3997.093
|
69
|
57.929
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Total
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5380.247
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72
|
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a.
Predictors: (Constant), interaksi, umur, jumlah air dalammakanan
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b.
Dependent Variable: berat jenis
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Coefficientsa
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Model
|
Unstandardized
Coefficients
|
Standardized Coefficients
|
t
|
Sig.
|
||
|
B
|
Std. Error
|
Beta
|
||||
|
1
|
(Constant)
|
980.543
|
65.228
|
|
15.033
|
.000
|
|
jumlah
air dalammakanan
|
.138
|
.124
|
2.840
|
1.116
|
.268
|
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umur
|
4.716
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6.053
|
.281
|
.779
|
.439
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interaksi
|
-.015
|
.011
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-3.333
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-1.298
|
.199
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a.
Dependent Variable: beratjenis
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Y
= β0+ β1X1 +β2X2 +β3X3
IMT
= -980.543 + 0.138 AMA + 4.716umur
- 0.015 interaksi AMA danumur
Hipotesaintersepdan
slop = Setiapkenaikanjumlah air
dalammakanandanumurmempengaruhiberatjenisurinnamuninteraksikeduanyatidakmempengaruhiberatjenisurin
.
Latihan 2
|
Variabel
|
β
|
Sβ
|
Partial F
|
|
Umur
|
1.02892
|
0.50177
|
4.2049
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IMT
|
10.45104
|
11,9623
|
1.310
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RKK
|
-0.53744
|
23.23004
|
0.000529
|
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Umur*RKK
|
0.43733
|
0,286
|
0.376
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IMT*RKK
|
-3.70682
|
10.76763
|
0.118336
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Intersep
|
48.61271
|
-
|
-
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Model
regresi :
Y
= 48.61271 + 1.02892 + 0.50177 UMUR
Y
= 48.61271 + 10.45104 + 9.131 IMT
Y
= 48.61271 – 0.53744 + 23.23004 RKK
Y
= 48.61271 + 0.43733 + 0.7132 UMUR*RKK
Y
= 48.61271 – 3.70682 + 10.76763 IMT*RKK
Y
= 48.61271 + β1X1 + β2X2 + β3X3 +β4X4 +β5X5
=
48.61271 + 1.02892 U + 10.45104 IMT – 0.53744 RKK + 0.43733 U*RKK – 3.70682
IMT*RKK
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